Q:

write the equation of the line that passes through (7,6) and (-1,2) in slope intercept form​

Accepted Solution

A:
The equation of line passing through (7,6) and (-1,2) in slope intercept form is:[tex]y=\frac{1}{2}x+\frac{5}{2}[/tex]Step-by-step explanation:Given(x1,y1) = (7,6)(x2,y2) = (-1,2)The general form of slope-intercept form of equation is:[tex]y=mx+b[/tex]We have to find the slope first[tex]m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{2-6}{-1-7}\\\\m=\frac{-4}{-8}\\\\m=\frac{1}{2}[/tex]Putting the value of slope in the equation[tex]y=\frac{1}{2}x+b[/tex]To find the value of b, putting (-1,2) in the equation[tex]2=\frac{1}{2}(-1)+b\\2=-\frac{1}{2}+b\\2+\frac{1}{2}=b\\b=\frac{4+1}{2}\\b=\frac{5}{2}[/tex]Putting the value of m and b in equation [tex]y=\frac{1}{2}x+\frac{5}{2}[/tex]The equation of line passing through (7,6) and (-1,2) in slope intercept form is:[tex]y=\frac{1}{2}x+\frac{5}{2}[/tex]Keywords: Slope intercept form, slopeLearn more about equation of line at:brainly.com/question/2397962brainly.com/question/2403985#LearnwithBrainly