Graph the line that passes through the point (-3,0) and has a slope -3.

Answer:See picture below.Step-by-step explanation:First we will find the equation of this said line.We can use the formula y - y1 = m(x -x1), where (x1, y1) is a point that belongs to the line and m is the slopeIn this case we have the point (-3, 0), therefore x1 = -3, y1 = 0, m = -3.[tex]y-y_{1}=m(x-x_{1} )\\y-0=-3(x-(-3))\\y=-3(x+3)\\y=-3x-9\\[/tex]Therefore, the equation of the line is y = -3x - 9. We already know that the intersection with the y-axis is (-3,0). To find the intersection with the x-axis we will make x = 0 in the equation.[tex]y=-3(0)-9\\y=-9[/tex]Therefore, the intersection with the x-axis would be (0,-9)Now we can take these two points ((0,9), (-3,0)) and draw the line that passes through both of them and we will have the line we're looking for.