12x−39≤9 AND−4x+3<−6, just solving for xplease answer ASAP

Answer:Solving for x in 12x − 39 ≤ 9 and −4x + 3 < −6 we get 2.25 < x ≤ 4 Solution:Need to find the value of x which satisfies following two given expressions 12x − 39 ≤ 9      ------(1) −4x + 3 < −6     ------ (2) Lets first solve expression (1) 12x − 39 ≤ 9   Adding 39 on both sides , we get 12x−39 + 39  ≤ 9  +39 =>12x ≤ 48 => x  ≤ 48/12 => x ≤ 4     Now solving expression (2) −4x+3<−6      => -4x < -6 – 3 => -4x < -9  => 4x > 9 => x > 9/4 => x > 2.25 So from solution of expression (1) and (2) , we get x ≤ 4   and x > 2.25 Hence required value of x is 2.25 < x ≤ 4.